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Text Solution

`(Momega_(0))/(M+6m)``(Momega_(0))/m``(Momega_(0))/(M+12m)``omega_(0)`

Answer :

ASolution :

From conservation of angular momentum <br> `(ML^(2))/12 omega_(0)=[(ML^(2))/12+2m(L/2)^(2)]omega` <br> `omega(M/(M+6m))omega_(0)`